Add solution for "Day 21: Keypad Conundrum", part 2

This commit is contained in:
2025-06-09 18:28:16 +02:00
parent ab26563e34
commit 83c66682ef
7 changed files with 156 additions and 31 deletions

View File

@@ -22,8 +22,11 @@ KeypadRobot::KeypadRobot(const std::map<char, Point2>&& keypad, const Point2&& f
{
}
std::string KeypadRobot::calcInputKeys(const std::string& targetOutputKeys) const
KeypadPatternTransformation KeypadRobot::calcTransformation(const std::string& targetOutputKeys) const
{
KeypadPatternTransformation result{};
result.accumulatedLengths.push_back(targetOutputKeys.size());
std::ostringstream stream{};
Point2 position{ 0, 0 };
for (const char c : targetOutputKeys)
@@ -32,37 +35,44 @@ std::string KeypadRobot::calcInputKeys(const std::string& targetOutputKeys) cons
// This specific order of robot arm movements aims to reduce resulting combinations of 'A' and '<' for the
// second robot, which expand to more key presses starting with the third robot.
bool horizontalFirst{ (next.x < position.x && !(next.x == forbidden_.x && position.y == forbidden_.y)) ||
(position.x == forbidden_.x && next.y == forbidden_.y) };
bool horizontalFirst{ (next.x < position.x && !isForbidden(next.x, position.y)) ||
isForbidden(position.x, next.y) };
if (horizontalFirst)
{
move(stream, next.x - position.x, '>', '<');
move(stream, next.x - position.x, '>', '<', result.nDuplicates);
}
move(stream, next.y - position.y, 'v', '^');
move(stream, next.y - position.y, 'v', '^', result.nDuplicates);
if (!horizontalFirst)
{
move(stream, next.x - position.x, '>', '<');
move(stream, next.x - position.x, '>', '<', result.nDuplicates);
}
stream << 'A';
result.parts.push_back(stream.str());
stream.str("");
position = next;
}
return stream.str();
return result;
}
void KeypadRobot::move(std::ostringstream& stream, const int delta, const char positive, const char negative) const
void KeypadRobot::move(std::ostringstream& stream, const int delta, const char positive, const char negative,
int& nDuplicates) const
{
if (delta > 0)
{
for (int i{ 0 }; i < delta; i++)
{
stream << positive;
}
stream << positive;
nDuplicates += delta - 1;
}
else
else if (delta < 0)
{
for (int i{ 0 }; i < -delta; i++)
{
stream << negative;
}
stream << negative;
nDuplicates -= delta + 1;
}
}
bool KeypadRobot::isForbidden(const int x, const int y) const
{
return x == forbidden_.x && y == forbidden_.y;
}