105 lines
3.4 KiB
Rust
105 lines
3.4 KiB
Rust
use crate::solvers::Solver;
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use std::io::BufRead;
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pub struct GiftShop {}
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impl GiftShop {
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const RANGES_SPLIT_CHAR: char = ',';
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}
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impl Solver for GiftShop {
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const PUZZLE_INDEX: u8 = 2;
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const PUZZLE_NAME: &'static str = "Gift Shop";
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fn process_data<R: BufRead>(&self, reader: R) -> (u64, u64) {
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let mut invalid_ids_sum = 0;
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for line in reader.lines().map_while(Result::ok) {
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let ranges = line.split(Self::RANGES_SPLIT_CHAR);
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for range in ranges {
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if let Some(range) = Range::try_from_str(range) {
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invalid_ids_sum += range.sum_invalid_ids();
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}
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}
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}
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(invalid_ids_sum, 0)
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}
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}
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struct Range {
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first: u64,
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last: u64,
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digits: u32,
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}
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impl Range {
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const SPLIT_CHAR: char = '-';
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fn try_from_str(s: &str) -> Option<Self> {
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// Parses first and last IDs from range string.
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let ids: Vec<u64> = s
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.split(Self::SPLIT_CHAR)
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.map(|s| {
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s.parse()
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.expect("could not parse id range, must be integers")
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})
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.collect();
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assert_eq!(ids.len(), 2, "could not parse id range, must be two values");
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// Calculates the logs of first and last IDs and checks the size of the range.
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let (a_log, b_log) = (ids[0].ilog10(), ids[1].ilog10());
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assert!(b_log < a_log + 2, "id range is unexpectedly large");
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if a_log == b_log {
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if a_log % 2 == 0 {
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// Skips this range if the first and last IDs are both odd.
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None
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} else {
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Some(Range {
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first: ids[0],
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last: ids[1],
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digits: a_log + 1,
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})
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}
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} else {
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if a_log % 2 == 0 {
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// First ID becomes the smallest ID with a number of digits equal to 'a_log + 2'.
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Some(Range {
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first: 10_u64.pow(b_log),
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last: ids[1],
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digits: b_log + 1,
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})
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} else {
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// Last ID becomes the largest ID with a number of digits equal to 'a_log + 1'.
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Some(Range {
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first: ids[0],
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last: 10_u64.pow(b_log) - 1,
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digits: b_log,
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})
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}
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}
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}
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fn sum_invalid_ids(&self) -> u64 {
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let power10 = 10_u64.pow(self.digits / 2);
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let first_left = self.first / power10;
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let last_left = self.last / power10;
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let first_right = self.first % power10;
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let last_right = self.last % power10;
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let mut sum = 0;
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// Checks, for a given range AB-CD, whether invalid ID AA is in the range.
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if first_left >= first_right && (first_left < last_left || first_left <= last_right) {
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sum += first_left;
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}
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// Calculates the sum of the in-between invalid IDs directly without loop, but we need to
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// explicitly check whether there are any values.
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if first_left + 1 <= last_left {
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sum += (first_left + last_left) * (last_left - first_left - 1) / 2;
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}
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// Checks, for a given range AB-CD, whether invalid ID CC is in the range.
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if first_left != last_left && last_left <= last_right {
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sum += last_left;
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}
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sum * (power10 + 1)
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}
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}
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